Suppose you have the 7.57μF7.57μF capacitor of a heart defibrillator at a potential difference of 18.89×104V18.89×104V. What charge, in millicoulombs, is stored on the capacitor.
Added by Mario D.
Step 1
To find the charge stored on the capacitor, we can use the formula: \[ Q = C \times V \] where: - \( Q \) is the charge in coulombs, - \( C \) is the capacitance in farads, - \( V \) is the potential difference in volts. Show more…
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