00:01
In this problem, we have been given that there is a 20 kg box.
00:05
And this 20 kg box is lifted up to a height of one meter.
00:11
So we need to determine here the work that we do in lifting this box.
00:16
So whatever work is done, that's done against the force of gravity.
00:21
So work should be sufficiently enough to overcome the work done by the gravity.
00:27
So that should be plus mgh.
00:30
So that's 20 times 9 .8 times 1.
00:34
And this comes out to be 196 jules.
00:38
And now here we consider that instead of lifting it directly vertically up, we lift this box with a ramp which is making the angle of 30 degree with the horizontal.
00:53
And this box is lifted up by a 1 meter ramp.
00:58
So we need to determine here the force that's required.
01:03
To push this box above the ramp or up to the ramp at the highest point that we have been given with the constant speed.
01:11
So as the speed is constant, that means the acceleration is zero.
01:14
So that means the force must be equal along both the directions of the incline.
01:23
But nevertheless, we just need to find out the force.
01:28
So here we draw the free body diagram.
01:30
So the weight will be m into g.
01:32
That's 20 times 9 .8, which is.
01:35
Is 19 .6 newtons, 196, because here we have 20 not 2.
01:44
So that will be 196 newtons.
01:47
So if the weight is 196 newtons, we see that there are two components of weight.
01:52
So if we break this weight into two components, geometrically we get this angle as 30 degree.
01:57
So it will be 196 cost 30.
02:01
And that is approximately 169 .7...