Question

Suppose you’re trying to predict sleep deprivation among adults ages 18-65. You think that having young children at home may be a good predictor of sleep deprivation. So you estimate the following model as a linear probability model using OLS. Pr(sleep_deprived=1|X)=0.40+0.10yngkid The standard error of beta0hat is 0.05. The standard error of beta1hat is 0.02. What’s the probability that someone is sleep deprived if he/she has two young kids? Finally, you estimate a bivariate model using logit that relates marriage status to the probability of sleep deprivation. Specifically, the married variable equals 1 if the person is married and equals 0 otherwise. You find: Pr(sleep_deprived=1|X)=-0.35+0.21married The standard error of beta0hat is 0.26. The standard error of beta1hat is 0.09. What’s the predicted probability of sleep deprivation for someone who is married? Round to three decimal places. QUESTION 10 Does marriage status have a statistically significant effect on the probability of sleep deprivation? Compute the p-value. Round to 4 decimal places. i need q 10

          Suppose you’re trying to predict sleep deprivation among adults ages 18-65. You think that having young children at home may be a good predictor of sleep deprivation. So you estimate the following model as a linear probability model using OLS.
 Pr(sleep_deprived=1|X)=0.40+0.10*yngkid
 The standard error of beta0hat is 0.05.
The standard error of beta1hat is 0.02.
What’s the probability that someone is sleep deprived if he/she has two young kids?
Finally, you estimate a bivariate model using logit that relates marriage status to the probability of sleep deprivation. Specifically, the married variable equals 1 if the person is married and equals 0 otherwise. You find:
 Pr(sleep_deprived=1|X)=-0.35+0.21*married
 The standard error of beta0hat is 0.26.
The standard error of beta1hat is 0.09.
What’s the predicted probability of sleep deprivation for someone who is married? Round to three decimal places.
QUESTION 10
Does marriage status have a statistically significant effect on the probability of sleep deprivation? Compute the p-value. Round to 4 decimal places.
i need q 10

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Added by Soledad L.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

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Solved by Expert David Nguyen

10/25/2022

Step 1

The model is given as: Pr(sleep_deprived=1|X) = 0.40 + 0.10*yngkid To find the probability for someone with two young kids, we plug in yngkid = 2: Pr(sleep_deprived=1|X) = 0.40 + 0.10*2 = 0.40 + 0.20 = 0.60 So, the probability of sleep deprivation for someone Show more…

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Suppose you’re trying to predict sleep deprivation among adults ages 18-65. You think that having young children at home may be a good predictor of sleep deprivation. So you estimate the following model as a linear probability model using OLS. Pr(sleep_deprived=1|X)=0.40+0.10*yngkid The standard error of beta0hat is 0.05. The standard error of beta1hat is 0.02. What’s the probability that someone is sleep deprived if he/she has two young kids? Finally, you estimate a bivariate model using logit that relates marriage status to the probability of sleep deprivation. Specifically, the married variable equals 1 if the person is married and equals 0 otherwise. You find: Pr(sleep_deprived=1|X)=-0.35+0.21*married The standard error of beta0hat is 0.26. The standard error of beta1hat is 0.09. What’s the predicted probability of sleep deprivation for someone who is married? Round to three decimal places. QUESTION 10 Does marriage status have a statistically significant effect on the probability of sleep deprivation? Compute the p-value. Round to 4 decimal places. i need q 10

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Transcript

00:01 Hi, i'm david and i'm here to help you and change your question.

00:03 In the question here, let me bring it up for you.

00:06 We're talking about the competence interval for the difference between the two sample proportions.

00:11 Here we have the confidence interval for the p1 minus the p2.

00:15 It will be the ph1 minus the ph2, then plus and minus the critical value z and 4 over 2, times square root of the ph1 times 1 minus ph1 over and 1, plus the ph2 times 1 minus the ph2.

00:30 Over the n2.

00:32 Now in this question here we have the 8 % on the first 30 days why this proportion is 8 .8 % for the oregon residents.

00:46 So we will have this data are based on the simple random of the we have the n1 equal to the california will be the 11545 and we have the ph 1 equals to the 8 % will be the 0 .08, when the n2 equals 2, 4 ,691, p .h2 equal to the 8 .8 % will be the 088.

01:15 And now, the first question 1 asks not to find the point estimate.

01:22 So from here, the point estimate is equal to the p .h1 minus the p .h2.

01:33 And then we get equal to the 0108 minus 018, then get equal to the 01008.

01:39 Then get equal to the 0108 minus here.

01:42 And then from the next one, i'm going to find the margin of the error.

01:49 So the matching of the error will be the quantity on the right here, denoted by the e.

01:53 Now we need to find the z and 4 over 2.

01:56 So z and 4 over 2 and the 95 % confidence.

02:00 And 4 equal to the 5 % divided by 2, equal to 2, equal to 2, the 2 .5 % which is equal to the 025.

02:06 It will look up the z table, this value equals to 1 .96...

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