Suppose Z follows the standard normal distribution. Use the calculator provided, or this table, to determine the value of so that the following is true. P ( c ≤ Z ≤ 0.86) = 0.7868 Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places.
Added by Lisa B.
Step 1
86) = 0.8051 from the standard normal distribution table. We want to find c such that P(c ≤ Z ≤ 0.86) = 0.7868. This is equivalent to finding c such that P(Z ≤ 0.86) - P(Z ≤ c) = 0.7868. Show more…
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