Switch 1 has been in position a and switch 2 has been closed for a long time. At $t = 0$, switch 1 moves instantaneously to position b. 400 µs late, switch 2 opens. Determine the the voltage $v_o$ 1 ms after switch 1 makes contact with terminal b.
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The 35 kΩ resistors are in series, resulting in 70 kΩ. This is in parallel with the 5 kΩ resistor, giving an equivalent resistance of: $R_{eq1} = \frac{70k \times 5k}{70k + 5k} = \frac{350k^2}{75k} = \frac{14k}{3} \approx 4.67 k\Omega$ Show more…
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