00:01
Hi, here in this given problem there are four systems each having the masses and the gap between the masses.
00:09
So first of all, for system a gravitational force of attraction acting between the given masses, both the masses are m each having gap are between them.
00:25
So, using newton's law of gravitation, this is g m square by r square.
00:32
Then for system and let it be f a, then for system b, fb will be this time first object is having mass m, second is having mass 2m.
00:52
And the gap between them, this is twice of r.
00:56
So it will remain g m square by 2r square.
01:02
Then for system c, fc, this time both the objects, the first object, this is having a mass 3m, the second one that is 2m, and the gap between them, this is again 2r.
01:22
So here it will be 3, 2, 6, but no, this 2, 1 of the 2 will be cancelled.
01:27
Leaving behind 3m square by one of the 2 will be remaining 2 r square...