Question

Systolic blood pressure levels above 120 mm Hg are considered to be high. For the 100 systolic blood pressure levels listed in the accompanying data set, the mean is 123.54000 mm Hg and the standard deviation is 14.82246 mm Hg. Assume that a simple random sample has been selected. Use a 0.05 significance level to test the claim that the sample is from a population with a mean greater than 120 mm Hg. Body and exam measurements are from 100 subjects. SYSTOLIC is systolic blood pressure (mm Hg). 112 112 116 104 126 130 114 126 130 114 122 132 106 112 134 114 128 132 114 118 124 128 132 154 116 122 130 102 110 142 120 134 136 128 134 140 94 112 140 114 120 144 100 136 156 108 112 112 120 142 146 108 132 164 120 126 136 96 112 142 92 114 122 104 124 128 126 128 134 102 108 120 116 128 138 112 120 160 132 134 146 102 132 154 112 114 132 100 116 138 106 124 136 114 122 144 116 118 136 110

          Systolic blood pressure levels above 120 mm Hg are considered to be high. For the 100 systolic blood pressure levels listed in the accompanying data set, the mean is 123.54000 mm Hg and the standard deviation is 14.82246 mm Hg. Assume that a simple random sample has been selected. Use a 0.05 significance level to test the claim that the sample is from a population with a mean greater than 120 mm Hg.

Body and exam measurements are from 100 subjects. SYSTOLIC is systolic blood pressure (mm Hg).

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Added by Justin R.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

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Solved by Expert Benjamin Densmore

05/10/2023

Step 1

The claim is that the sample is from a population with a mean greater than 120 mm Hg. So, the null hypothesis (H0) is that the population mean is equal to 120 mm Hg, and the alternative hypothesis (H1) is that the population mean is greater than 120 mm Hg. H0: μ Show more…

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Systolic blood pressure levels above 120 mm Hg are considered to be high. For the 100 systolic blood pressure levels listed in the accompanying data set, the mean is 123.54000 mm Hg and the standard deviation is 14.82246 mm Hg. Assume that a simple random sample has been selected. Use a 0.05 significance level to test the claim that the sample is from a population with a mean greater than 120 mm Hg. Body and exam measurements are from 100 subjects. SYSTOLIC is systolic blood pressure (mm Hg). 112 112 116 104 126 130 114 126 130 114 122 132 106 112 134 114 128 132 114 118 124 128 132 154 116 122 130 102 110 142 120 134 136 128 134 140 94 112 140 114 120 144 100 136 156 108 112 112 120 142 146 108 132 164 120 126 136 96 112 142 92 114 122 104 124 128 126 128 134 102 108 120 116 128 138 112 120 160 132 134 146 102 132 154 112 114 132 100 116 138 106 124 136 114 122 144 116 118 136 110

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Transcript

00:01 Okay, in this problem, we have that systolic blood pressure levels above 120 are considered to be high.

00:07 And so we have 100 blood pressure levels listed in this data set.

00:11 And the mean is found to be 122 .4.

00:14 And the standard deviation is found to be 16 .08563.

00:18 So we're going to assume that a simple random sample has been selected.

00:21 And we're going to use a five significance level, so 95 % confidence level, to test the and we're going to claim that the sample is from the sample from a population with a mean greater than 120 millimeters.

00:32 Okay, so what we're saying is that our null hypothesis is that our mean, our mu here is equal to what was it 120.

00:43 All right, so we'll have an alternate hypothesis.

00:45 And that is that our mu, that's an a there, and a, there we go.

00:50 Our alternate hypothesis is that our mu is not equal to 120.

00:53 All right, so we have our x bar, well, we have n, right? we have 100 things that we found.

00:58 And from those 100 things, we saw that our x bar is 122 .4 and with four zeros after that.

01:06 And then our sample standard deviation is found to be 16 .08563.

01:13 Okay, so what we're going to do is we're going to take our x bar.

01:18 So we're going to perform a confidence interval test.

01:21 We'll have our x bar, and then we're going to do plus and minus the z score that's associated with 0 .96.

01:26 And then we're going to multiply that times our standard deviation over the square root of the number of things that we have sampled.

01:35 Okay, so our x bar we showed was 122 .4, plus or minus the z score for 96, or sorry, not 96...

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