Question

t-Test: Two-Sample Assuming Unequal Variances Current New Mean 270.275 267.5 Variance 76.61474359 97.94871795 Observations 40 40 Hypothesized Mean Difference 0 df 77 t Stat 1.328361594 P(T<=t) one-tail 0.093991211 t Critical one-tail 1.664884538 P(T<=t) two-tail 0.187982421 t Critical two-tail 1.991254363 In the graphs above, the lighter blue color represents the non-rejection region for the null hypothesis while the darker blue color represents the rejection region. Decision time. You must now make a decision about whether to reject your null hypothesis or fail to reject your null hypothesis and present your finding to the Par, Inc. research team. As their consultant, your decision must be 1) correct, and 2) explained in "plain English" so that everyone within Par, Inc. can understand your recommendation and why. Reject H0 because the p-value is less than ? = .05. In my analysis, since the p-value is less than ? = .05, the t-statistic falls to the right of the t-critical value, placing it in the rejection region. There is evidence to support the conclusion that the current golf ball outdistances the new model substantially, bringing the new coating into question. I recommend stopping development of the new cut-resistant golf ball at this time. Fail to reject H0 because the p-value is greater than ? = .05. In my analysis, since the p-value is greater than ? = .05, the t-statistic falls to the left of the t-critical value, placing it in the non-rejection region. There is evidence to support the conclusion that the current golf ball and the new model do not differ significantly in their average drive distance. I recommend continuing development of the new cut-resistant golf ball at this time. Fail to reject H0 because the p-value is greater than ? = .05. In my analysis, since the p-value is greater than ? = .05, the t-statistic falls to the left of the t-critical value, placing it in the rejection region. There is evidence to support the conclusion that the current golf ball outdistances the new model substantially, bringing the new coating into question. I recommend stopping development of the new cut-resistant golf ball at this time. Reject H0 because the p-value is greater than ? = .05. In my analysis, since the p-value is greater than ? = .05, the t-statistic falls to the left of the t-critical value placing it in the non-rejection region. There is evidence to support the conclusion that the new golf ball outdistances the current model substantially. I recommend continuing development of the new cut-resistant golf ball at this time.

t-Test: Two-Sample Assuming Unequal Variances

Current New
Mean 270.275 267.5
Variance 76.61474359 97.94871795
Observations 40 40
Hypothesized Mean Difference 0
df 77
t Stat 1.328361594
P(T<=t) one-tail 0.093991211
t Critical one-tail 1.664884538
P(T<=t) two-tail 0.187982421
t Critical two-tail 1.991254363

In the graphs above, the lighter blue color represents the non-rejection region for the null hypothesis while the darker blue color represents the rejection region.

Decision time. You must now make a decision about whether to reject your null hypothesis or fail to reject your null hypothesis and present your finding to the Par, Inc. research team. As their consultant, your decision must be 1) correct, and 2) explained in "plain English" so that everyone within Par, Inc. can understand your recommendation and why.

Reject H0 because the p-value is less than ? = .05. In my analysis, since the p-value is less than ? = .05, the t-statistic falls to the right of the t-critical value, placing it in the rejection region. There is evidence to support the conclusion that the current golf ball outdistances the new model substantially, bringing the new coating into question. I recommend stopping development of the new cut-resistant golf ball at this time.

Fail to reject H0 because the p-value is greater than ? = .05. In my analysis, since the p-value is greater than ? = .05, the t-statistic falls to the left of the t-critical value, placing it in the non-rejection region. There is evidence to support the conclusion that the current golf ball and the new model do not differ significantly in their average drive distance. I recommend continuing development of the new cut-resistant golf ball at this time.

Fail to reject H0 because the p-value is greater than ? = .05. In my analysis, since the p-value is greater than ? = .05, the t-statistic falls to the left of the t-critical value, placing it in the rejection region. There is evidence to support the conclusion that the current golf ball outdistances the new model substantially, bringing the new coating into question. I recommend stopping development of the new cut-resistant golf ball at this time.

Reject H0 because the p-value is greater than ? = .05. In my analysis, since the p-value is greater than ? = .05, the t-statistic falls to the left of the t-critical value placing it in the non-rejection region. There is evidence to support the conclusion that the new golf ball outdistances the current model substantially. I recommend continuing development of the new cut-resistant golf ball at this time.

t-Test: Two-Sample Assuming Unequal Variances

Current New
Mean 270.275 267.5
Variance 76.61474359 97.94871795
Observations 40 40
Hypothesized Mean Difference 0
df 77
t Stat 1.328361594
P(T<=t) one-tail 0.093991211
t Critical one-tail 1.664884538
P(T<=t) two-tail 0.187982421
t Critical two-tail 1.991254363

In the graphs above, the lighter blue color represents the non-rejection region for the null hypothesis while the darker blue color represents the rejection region.

Decision time. You must now make a decision about whether to reject your null hypothesis or fail to reject your null hypothesis and present your finding to the Par, Inc. research team. As their consultant, your decision must be 1) correct, and 2) explained in "plain English" so that everyone within Par, Inc. can understand your recommendation and why.

Reject H0 because the p-value is less than ? = .05. In my analysis, since the p-value is less than ? = .05, the t-statistic falls to the right of the t-critical value, placing it in the rejection region. There is evidence to support the conclusion that the current golf ball outdistances the new model substantially, bringing the new coating into question. I recommend stopping development of the new cut-resistant golf ball at this time.

Fail to reject H0 because the p-value is greater than ? = .05. In my analysis, since the p-value is greater than ? = .05, the t-statistic falls to the left of the t-critical value, placing it in the non-rejection region. There is evidence to support the conclusion that the current golf ball and the new model do not differ significantly in their average drive distance. I recommend continuing development of the new cut-resistant golf ball at this time.

Fail to reject H0 because the p-value is greater than ? = .05. In my analysis, since the p-value is greater than ? = .05, the t-statistic falls to the left of the t-critical value, placing it in the rejection region. There is evidence to support the conclusion that the current golf ball outdistances the new model substantially, bringing the new coating into question. I recommend stopping development of the new cut-resistant golf ball at this time.

Reject H0 because the p-value is greater than ? = .05. In my analysis, since the p-value is greater than ? = .05, the t-statistic falls to the left of the t-critical value placing it in the non-rejection region. There is evidence to support the conclusion that the new golf ball outdistances the current model substantially. I recommend continuing development of the new cut-resistant golf ball at this time.

Added by Virginia S.

Question

Please give Ace some feedback