The diameter of the cable is \(1.5 \times 10^{-2} \, \text{m}\).
The radius \(r\) is half of the diameter:
\[ r = \frac{1.5 \times 10^{-2}}{2} = 0.75 \times 10^{-2} \, \text{m} \]
The cross-sectional area \(A\) is given by the formula for the area of a circle:
\[
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