The iodoform test (NaOH, I2-KI) converts a methyl ketone (RCOCH3) to a triiodomethyl ketone (RCOCI3). The -CI3 group can then act as a leaving group to form iodoform CHI3.
a) Suggest a mechanism for the conversion of RCOCH3 to RCOCI3. (Hint: What happens to a ketone in base?)
b) Would the formation of ROCI3 work as well if the catalyst were HI?
Yes or No? (Circle one)
c) Describe how you came to your conclusion.