00:01
In this question, there is a rod.
00:02
It is made of two material.
00:05
The one is cast iron and the second one is aluminium.
00:09
This is aluminium and this is made for cast iron.
00:14
The length is 1 .3 metre.
00:16
The length of aluminium is 2 .6 metre.
00:19
And the diameter of this rod is 0 .40 centimeter.
00:26
So you will get the radius that is 0 .20 centimeter.
00:31
Now the young modelers of aluminum is given as 7 times 10 power 10 pascals.
00:39
And young modelers for cast iron is 100 times 10 power 10 pascal.
00:47
And the force is subjected in this rod, that is equal to 5 .5 times 10 power 3 neuter.
00:55
So we are calculating the change in elongation.
01:00
Because force is applied, so there is a chances to elongate this rod.
01:06
So delta l is equal to delta l for cast iron plus delta l for alumnium.
01:13
So we are using the hooks law...