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List-I A. Inspection of raw and intermediate products, In-service damage inspection List-II 1. Timing B. Floor, Centralized and Combined 2. Place Inspection C. Sampling and 100% Inspection 3. Application D. Off-line and On-line inspection 4. Number of samples inspected

          List-I
A. Inspection of raw and intermediate
products, In-service damage
inspection
List-II
1. Timing
B. Floor, Centralized and Combined
2. Place
Inspection
C. Sampling and 100% Inspection
3. Application
D. Off-line and On-line inspection
4. Number of samples inspected
        
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List-I
A. Inspection of raw and intermediate
products, In-service damage
inspection
List-II
1. Timing
B. Floor, Centralized and Combined
2. Place
Inspection
C. Sampling and 100% Inspection
3. Application
D. Off-line and On-line inspection
4. Number of samples inspected

Added by Pamela B.

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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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able[[List-I List-II,],[ able[[A. Inspection of raw and intermediate],[products, In-service damage],[inspection]],1. Timing],[ able[[B. Floor, Centralized and Combined],[Inspection]],2. Place],[C. Sampling and 100% Inspection,3. Application],[D. Off-line and On-line inspection,4. Number of samples inspected]] List-I List-II A. Inspection of raw and intermediate 1.Timing products, inspection In-service damage B. Floor, Centralized and Combined 2.Place Inspection C. Sampling and 100% Inspection 3.Application D. Off-line and On-line inspection 4.Number of samples inspected
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Transcript

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00:01 Hello students here the first bit a bit it is since all as non -conformities is within these limits come up we can conclude that process is in control and for bit b here given that n is equal to 4 and m is equal to 18 from the table we say that total number of defects is 27 then the central line c bar is 27 by 18 that is equal to 1 .5 and the control limits lower control limit is equal to c bar minus 3 root c that is equal to 1 .5 minus 3 into 1 point square root of 1 .5 that is equal to minus 2 .17 and the upper control limit that is equal to c bar plus 3 into root c that is equal to 1 .5 plus 3 into square root of 1 .5 that is equal to 5 .17 i hope you understand this...
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