\tan a = \cot(a + 10^\circ)
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$tan \alpha = \frac{1}{tan(\alpha + 10^\circ)}$ Show more…
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In Problems $37-54,$ use Fundamental Identities and/or the Complementary Angle Theorem to find the exact value of each expression. Do not use a calculator. $$\tan 10^{\circ} \cot 10^{\circ}$$
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Assertion: If $\cot ^{-1}(\sqrt{\cos \alpha})-\tan ^{-1}(\sqrt{\cos \alpha})=x$, then $\sin x=\tan ^{2} \frac{\alpha}{2}$ Reason: $\tan ^{-1} x-\tan ^{-1} y=\tan ^{-1}\left(\frac{x-y}{1+x y}\right)$
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