00:01
A 12 .01 gram sample of tartaric acid was combusted, which produced 14 .08 grams of carbon dioxide and 4 .32 grams of water.
00:12
And we are asked to find the empirical formula of the totoric acid, which i represent as cx, h -y, o -z.
00:22
So we need to find our compositions of carbon, hydrogen, and oxygen.
00:27
So we'll start with the 14 .08 gram sample of co2.
00:38
Now we know that with 44 .01 grams of co2, we have one mole.
00:53
And with one mole of co2, we have one mole of carbon.
01:02
So this is equal to 0 .32 moles of carbon in the carbon, the 14 .0 .1.
01:14
Carbon dioxide sample.
01:18
In this, if we multiply this by the molar mass, not 12 .08 or other 12 .01 grams per mole, this is equal to 3 .84 grams of carbon in that sample.
01:38
This will be useful for finding the mass and moles of oxygen in the sample, but we'll get there in a minute.
01:46
We need to repeat this process for the water sample.
01:49
So 4 .32 grams of water.
01:55
Times there are 18 .02 grams of water and one mole of water.
02:09
And in one mole of water, there are two moles of hydrogen...