An object of mass M=0.24 kg is tied to a string of length L=9.801 m and the other end of the str

Name: An object of mass M=0.24 kg is tied to a string of length L=9.801 m and the other end of the string is held fixed, as shown in the figure. The object is given an initial minimum tangential speed (vA = 9.9 m/s) that causes it to rotate in a vertical circle. If TA is the tension in the string at the top, and TB is the tension at the bottom, then find TB - TA (in units of N). (Take g = 10 m/s²)
Uploaded: 2023-05-20T12:49:26-08:00
Duration: 2 min 46 s
Channel: Ivan Kochetkov
Description: An object of mass M=0.24 kg is tied to a string of length L=9.801 m and the other end of the string is held fixed, as shown in the figure. The object is given an initial minimum tangential speed (vA = 9.9 m/s) that causes it to rotate in a vertical circle. If TA is the tension in the string at the top, and TB is the tension at the bottom, then find TB - TA (in units of N). (Take g = 10 m/s²)

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Ivan Kochetkov · Accepted Answer

Step 1: At the top of the circle (point A), the forces acting on the object are tension in the s

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