00:01
Okay, so the mass of part a, let's first go over, what do we give? so we're given the radius of the proton, the mass of the proton, which is standard, and the proton must reach to a distance of 2r, where r is the radius of the proton.
00:13
That's where we know from part a, since there's a long question, i felt like that was important.
00:18
So from the law of conservation energy, we know that the energy at the initial step has to be equal to the final step.
00:24
So if you go over the expression for the initial step, which was two, there was two protons times two, times one, over mass of the proton, mass of the proton times its velocity since it's completely kind of it.
00:39
And at the end, it's going to be k times the charge of the proton, which is this e squared, because it's, we can just use e2 represent the charge times two r.
00:53
So now we know that we're solving for the velocity, so if we isolate for the variable v, we know that this will cancel all.
01:00
So all we need to do is divide.
01:02
By m and then squared with the whole thing so it becomes 2r and 3 rm by m is here and now we we need to square with because velocity is a square and now we see plug in all the values that we know for this so these are all values that we know so we can just plug the we can just substitute the values for the variables so a coom's constant is 9 times 10 to the power 9 times the charge of the proton which is 1 .6 times 10 to negative 19.
01:39
And this is all over two times the radius of the proton, which is 1 .6, 7 times 10 to the negative 27.
01:49
Remember, these are all standard units, so this is k, this is just kuom's constant.
01:55
This is kuom's and this is kg's and this is 27.
02:01
Let me make that clear.
02:03
Yep, this is 1 .6, 7.
02:05
In kgs times one point the distance is just 1 .2 times 10 to the negative 15 because it's two so it's to be solved like to just compute this in our calculator we can get that the velocity is 7 .58 meters 7 .58 definite not just meters 10 .58 times 10 to the 6 meters per second and that's part 8 from one to part b.
02:41
So we're given the sensor to this, we're given the distance to the center of the helium nuclei, we're given the mass, the nucleus, and from the conservation of energy, we know that once again, e initial is equal to e final, so if you use this expression once again, so let me just bring it down.
03:02
No, that's all right.
03:06
All right, there we go.
03:08
All right, we need to go with this bomb here first.
03:12
Let's bring this over.
03:17
Yep.
03:18
So let's bring that down here.
03:22
Yeah, so once again, it's the same equation.
03:25
But this time we're just using, we have four.
03:30
It's 2e electrons this time because of the helium nucleus, so this is a 2.
03:35
So there's just the 2 here because of the helium nuclei...