Question

TEST 4 - STATISTICS - GROUP A ? We toss tetrahedron $d: P(\triangle_1) = p; P(\triangle_2) = \frac{1}{4}; P(\triangle_3) = \frac{1}{4}; P(\triangle_4) = \frac{1}{4} - p$ For random variable: $x(\triangle_1) = -1$ $x(\triangle_2) = 0, x(\triangle_3) = 1, x(\triangle_4) = 2$ where -1, 0, 1, 2 denotes {profit or loss}. Based on {$x_1, x_2, ..., x_n$} find estimator of p a) by using moment generation method b) most likelihood principle

          TEST 4 - STATISTICS - GROUP A
? We toss tetrahedron $d:
P(\triangle_1) = p; P(\triangle_2) = \frac{1}{4}; P(\triangle_3) = \frac{1}{4}; P(\triangle_4) = \frac{1}{4} - p$
For random variable: $x(\triangle_1) = -1$
$x(\triangle_2) = 0, x(\triangle_3) = 1, x(\triangle_4) = 2$
where -1, 0, 1, 2 denotes {profit or loss}.
Based on {$x_1, x_2, ..., x_n$} find estimator of p
a) by using moment generation method
b) most likelihood principle

TEST 4 - STATISTICS - GROUP A
? We toss tetrahedron d:
P(1) = p; P(2) = (1)/(4); P(3) = (1)/(4); P(4) = (1)/(4) - p
For random variable: x(1) = -1
x(2) = 0, x(3) = 1, x(4) = 2
where -1, 0, 1, 2 denotes profit or loss.
Based on x1, x2, ..., xn find estimator of p
a) by using moment generation method
b) most likelihood principle

Added by Alfonso S.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Madhur L

05/21/2023

Step 1

Step 1: The probability of getting a specific face of the tetrahedron is p, and the probability of getting any of the other three faces is (1/4 - p). Show more…

Show all steps

Thanks for your feedback!

TEST 4 - STATISTICS - GROUP A We toss tetrahedron di P(A3)=p; P(A1)=1/4; P(A2)=1/4; P(A4)=1/4-p For random variable: X(tW1)=-1 X(tW2)=0, X(tW3)=1, X(tW4)=2 where -1, 0, 1, 2 denotes profit or loss. Based on tX1, X2, ... , Xn find estimator of p a) by using moment generation method b) most likelihood principle