(1 point) Solve the following initial value problem: \frac{dy}{dt} + 0.1ty = 9t with $y(0) = 1$. \begin{equation*} y = 90 - 89e^{(-0.05t)^2} \end{equation*}
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The given differential equation is dy + 0.1ty = 9t dt. To rewrite it in standard form, we need to move all the terms involving y to one side and all the terms involving t to the other side. dy + 0.1ty = 9t dt dy = -0.1ty dt + 9t dt Show more…
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