00:01
As here by the given section for the diagram in the given data here, diagram will be like this here.
00:12
So as here this one is our first block here and if we take here parting from this way and this one is our second block here.
00:22
This one is 20 m m.
00:26
As when this is equal to 10 m m.
00:29
And this complete height is equals to 40 m here and as here if we take an point like this point here this point coordinate is here 10 23 so as this distance is equal to x similarly as this distance is y bar here this one is x -par and this one is bhaar b this one is o here in this direction x -axis and in this direction here is y -axis so consider a section as shown in the figure let us take here a is equal to area equals to height into went which is height equals to 10 here area of first first block is a one height equals to as here length equals to 20 and breadth equals to 10 so 10 into 20 equals to 200 mm square here now come to x1 x1 equals to 10 mm similarly y1 is equals to here 35 m m here so consider the second this one is for the first block similarly now come to the second block here in the second block a to area is equal to height into width which is 10 into 30 which is equals to 300 m m square here and x2 is equals to in this question 10 mm and y 2 is equals to here 15 m here so consider calculation x bar equals to as we know that here combined combined modulus is combined mean equals to a into x 1 plus a 2 into x2 divided by area a 1 plus a 2 here so by simplifying this we can write this expression as 200 into 10 plus of 300 into 10 divided by complete term with 200 plus 300 here so by simplifying this x bar equals to 10 m m here now come to y bar y bar is equal to here a y 1 plus of a 2 a 1 by 1 plus a 2 by 2 divided by complete term with a 1 plus a 2 here which is equals to 200 into 35 plus of 300 into 15 divided by by complete term with divided by 200 plus 300 here.
02:39
So y bar is equal to 23 m here.
02:44
Centroid c is equal to as here, centroid equals to 1023.
02:48
In shown in the figure mentioned in the s, so initial inertia is ixx is equals to inertia is equals to i of x x1 plus a 1 into y minus y1 minus of y bar square plus of here i of x x x x 2 plus i 2 into y minus of y bar minus of y 2 square here so by substituting value here we can write this expression as here 20 into 10 less to the power 3 divided by 12 plus of 200 into 35 minus of 23 rest to the power 2 plus of 10 into 30 plus plus 10 into 30 plus plus 300 into 23 minus of 15 square here so by simplifying this 72 ,166 .66 .66 .m.
03:41
667 m.
03:43
Less to the power 4 here.
03:44
Neglate the direction stress because it is small compared to the binding stress here.
03:50
So m is equals to as here momentum, momentum to force p is equal to m equals to p into 187 plus of 17 here...