00:01
So we have an interface between air where the refractive index is n1, which is 1, and a plastic.
00:12
The refractive index of plastic is n2.
00:15
So we have a violet light coming in at an angle theta 1, and the theta 2 in, and the theta 2, in this case, is equal to 30 .40 .40 degrees.
00:33
So we can write this equation for violet.
00:37
We can say that n1, sine of theta 1 is equal to n2, sign of 30 .4 .00.
00:48
Or in other words, we can say sine of theta 1 is equal to n2 times sine of 30 .4 .00.
00:57
Now, when this same violet light is replaced by red light, so now we have red light.
01:08
So when this light is red, theta 1 is still equal to the same angle.
01:15
We're not changing it.
01:17
But now, the refractive index for the red light is less than that for violet light by 0 .040.
01:29
So therefore, what that means is for red, we can write a sign of theta 1 is equal to n2 minus 0 .04 and then times sign up...