00:02
Here we have p of x and we want to find p of one half.
00:07
And according to the remainder theorem, if we take p of x and we divide it by x minus one half, the remainder will be p of one half.
00:14
So getting ready for synthetic division, we put one half in the box and the coefficient of the polynomial, coefficients of the polynomial go in a row.
00:23
So we have 1x to the 5th, 1x to the 4th, negative 1x cubed, 0x squared, 0x and 3.
00:31
We need zeros to hold the places of the missing terms.
00:34
Then the process is we start by bringing down the first number.
00:38
Multiply it by the number in the box, one times one -half.
00:41
That's one -half.
00:42
We write it in the next space and we add the column.
00:44
So we get three halves.
00:46
Take that and multiply it by the number in the box.
00:48
We get three -fourths.
00:50
Put that in the next space and add the column.
00:51
We get negative one -fourth...