00:01
To solve the given system of equations.
00:02
So what i want you to do is take a look at the second equation.
00:05
Notice that x has already been isolated.
00:08
So the way i'm going to go about solving the system is by using substitution.
00:12
Because we know that x is equal to 2y minus 15, what we can do is we can substitute the expression 2y minus 15 in place of x in our first equation.
00:22
So when we do that, we'll have negative 5 times our x expression, which was 2y minus 15, and then we'll bring down the rest of the equation, plus 4y equals 3.
00:32
So now, as you can see, we just have an equation with y's.
00:35
So we can go ahead and solve this.
00:37
So first, i'll remove the parentheses by distributing negative 5 times 2y is negative 10y, and negative 5 times negative 15 is positive 75.
00:47
And then we'll bring down the plus 4y equals 3.
00:50
So then on the left -hand side, let's go ahead and combine our like terms...