A projectile is launched from ground level with an initial velocity of $v_0$ feet per second. Neglecting air resistance, its height in feet $t$ seconds after launch is given by $s = -16t^2 + v_0t$. Find the time(s) that the projectile will (a) reach a height of 160 ft and (b) return to the ground when $v_0 = 112$ feet per second.
Added by Dennis H.
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The given information is that the initial velocity (Vo) of the projectile is 112 feet per second. Show more…
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