A textile fiber manufacturer is investigating a new drapery yarn, which the company claims has a mean breaking strength of 12 kilograms with a standard deviation of 0.5 kilograms. A sample of four specimens were collected from a batch of material the mean breaking strength was determined to be 11.5 kilograms. Perform an appropriate test to determine if the mean breaking strength is less than 12 kilograms. Use 5% significance.
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Alternative hypothesis (Ha): The mean breaking strength of the new drapery yarn is less than 12 kilograms. Show more…
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A textile fiber manufacturer is investigating a new drapery yarn, which the company claims has a mean thread elongation of 12 kilograms with a standard deviation of 0.5 kilograms. The company wishes to test the hypothesis H0: μ = 12 against H1: μ < 12, using a random sample of 4 specimens. Round your answers to 4 decimal places. (a) What is the type I error probability if the critical region is defined as X < 11.5 kilograms? The type I error probability is 0.0228. (b) Find β for the case where the true mean elongation is 11.25 kilograms. β = 0.1587. (c) Find β for the case where the true mean is 11.5 kilograms. β = 0.0228.
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A textile fiber manufacturer is investigating a new drapery yarn, which the company claims has a mean thread elongation of 12 kilograms with a standard deviation of 0.5 kilograms. The company wishes to test the hypothesis H0 : μ = 12 against H1 : μ < 12, using a random sample of 4 specimens. Round your answers to 4 decimal places. (a) What is the type I error probability if the critical region is defined as x̄ < 11.5 kilograms? The type I error probability is 0.0228. (b) Find β for the case where the true mean elongation is 11.21 kilograms. β = 0.1587. (c) Find β for the case where the true mean is 11.5 kilograms. β = 0.5.
Textile fiber manufacturer investigating new drapery yarn, which the company claims has a mean thread elongation of 12 kilograms with a standard deviation of 0.5 kilograms. The company wishes to test the hypothesis Ho: μ = 12 against H1: μ < 12 using a random sample of n specimens. Calculate the p-value for the observed statistic. Round your final answer to five decimal places (e.g. 98.76543).
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