00:01
So, we have the given plot which is between g versus w.
00:10
So, here we have the plot, it is shown in the log scale.
00:17
We have the calculating this slope, let's calculate the slope of it.
00:27
The slope is equal to 20 log 1 minus of 20 log 10 divided by log 100 minus of log 10.
00:51
So, from here it would be 0 minus 20 divided by 2 minus 1 and from here the slope is equal to minus of 20 db per decimal.
01:09
So, one pole is added at w 10.
01:21
So, the transfer function can be written from the board plot as below that is g is equal to k multiplied by s plus 100 upon s plus 10.
01:45
So, at initial slope 0, constant k is there.
01:48
At w 10, slope is minus 20 db.
01:52
Initial slope is 0 and that is k constant.
02:05
At w is equal to 10, slope is equal to minus 20 db.
02:19
Pole is added at w 10.
02:22
At w 100, slope is equal to 0.
02:31
From the given plot, g at w is equal to 1 that is equal to 10 and that is equal to k multiplied by 100 plus j w divided by 10 plus j w and that is equal to 10...