00:01
Hi, here in this given problem there is a horizontal surface over which a sledge.
00:08
A sledge is being pulled by the man with the help of a rope.
00:20
The rope which is making an angle theta is equal to 37 degree with the horizontal force being exerted with the help of this rope that is 150 newton.
00:41
Mass of the sled, combined mass of the sled, that is m is equal to 46 kilograms.
00:53
Distance moved by the sled under the influence of this force s, that is 10 meters.
01:06
The speed of the sled was zero.
01:10
In the first part of the problem we have to find acceleration in the motion of the sled.
01:15
So this force will be resolved into two components.
01:20
F cost theta horizontal component, the forward force.
01:24
It will give a forward motion to the sled.
01:27
F sine theta it will make the sled lighter because it is accurate.
01:37
Upward.
01:38
So it will reduce the weight of the sled.
01:41
So using f cost theta net force acting on the sled in forward motion that will be put equal to m into a using newton's second law of motion.
01:54
So we get an expression for acceleration and that is f cost theta divided by m.
02:00
So here it is for f 150 into cosine of 37 degree and divided by mass which is 46 kilogram...