A ski resort tracks the proportion of seasonal employees who are rehired each season. Rehiring a seasonal employee is beneficial in many ways, including lowering the costs incurred during the hiring process such as training costs. A random sample of 859 full-time and 385 part-time seasonal employees from 2009 showed that 457 full-time employees were rehired compared with 186 part-time employees. (a) Is there a significant difference in the proportion of rehires between the full-time and part-time seasonal employees? (Use $\alpha = 0.10$.) (a-1) Choose the appropriate hypotheses. Assume $\pi_f$ is the proportion of full-time employees and $\pi_p$ is the proportion of part-time employees. $H_0: \pi_f - \pi_p = 0$ vs. $H_1: \pi_f - \pi_p \ne 0$ $H_0: \pi_f - \pi_p \ge 0$ vs. $H_1: \pi_f - \pi_p < 0$ $H_0: \pi_f - \pi_p \le 0$ vs. $H_1: \pi_f - \pi_p > 0$ (a-2) Specify the decision rule. (A negative value should be indicated by a minus sign. Round your answers to 3 decimal places.) Reject the null hypothesis if $z_{calc} >$ 1.645 or $z_{calc} <$ -1.645 (a-3) Find the test statistic $z_{calc}$. (Round intermediate calculations to 4 decimal places. Round your answer to 3 decimal places.) $z_{calc}$ 1.019 (a-4) Make a decision. We do not reject the null hypothesis. (a-5) Make a decision. We cannot conclude that there is a significant difference in the proportion of rehires between the full-time and part-time seasonal employees. (b) Find the p-value. (Round your answer to 4 decimal places.) p-value 0.3082
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H0: T1 = T2 (There is no significant difference in the proportion of renires between the full-time and part-time seasonal employees) H1: T1 ≠ T2 (There is a significant difference in the proportion of renires between the full-time and part-time seasonal employees) Show more…
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A ski resort tracks the proportion of seasonal employees who are rehired each season. Rehiring a seasonal employee is beneficial in many ways, including lowering the costs incurred during the hiring process such as training costs. A random sample of 859 full-time and 385 part-time seasonal employees from 2009 showed that 457 full-time employees were rehired compared with 186 part-time employees. (a) Is there a significant difference in the proportion of rehires between the full-time and part-time seasonal employees? (Use α = 0.10.) (a-1) Choose the appropriate hypotheses. Assume πF is the proportion of full-time employees and πP is the proportion of part-time employees. H0: πF – πP = 0 vs. H1: πF – πP ≠ 0 (a-2) Specify the decision rule. (A negative value should be indicated by a minus sign. Round your answers to 3 decimal places.) Reject the null hypothesis if zcalc > or zcalc < . (a-3) Find the test statistic zcalc. (Round intermediate calculations to 4 decimal places. Round your answer to 3 decimal places.) zcalc = (a-4) Make a decision. We the null hypothesis. (a-5) Make a decision. We conclude that there is a significant difference in the proportion of rehires between the full-time and part-time seasonal employees. (b) Find the p-value. (Round your answer to 4 decimal places.) p-value =
Clarissa B.
A ski resort tracks the proportion of seasonal employees who are rehired each season. Rehiring seasonal employees is beneficial in many ways, including lowering the costs incurred during the hiring process such as training costs. A random sample of 804 full-time and 333 part-time seasonal employees from 2009 showed that 481 full-time employees were rehired compared with 151 part-time employees. (a) Is there a significant difference in the proportion of rehires between the full-time and part-time seasonal employees? (Use α = 0.01.) (a-1) Choose the appropriate hypotheses. Assume p_F is the proportion of full-time employees and p_P is the proportion of part-time employees. H0: p_F = p_P Ha: p_F ≠ p_P (a-2) Specify the decision rule: (A negative value should be indicated by a minus sign. Round your answers to 3 decimal places.) Reject the null hypothesis if Zcalc ≤ -2.578 or Zcalc ≥ 2.578 (a-3) Find the test statistic Zcalc: (Round intermediate calculations to 4 decimal places. Round your answer to 3 decimal places.) Zcalc = 2.578
Supreeta N.
Joyce Kuhlman manages a regional financial center. She wishes to compare the productivity, as measured by the number of customers served, among three employees. Four days are randomly selected and the number of customers served by each employee is recorded as follows: Wolfe Simpson Korosa 55 66 47 54 76 51 59 67 46 56 71 48 At the 0.05 significance level, is there a difference in the productivity of the three employees? a. Enter the letter corresponding to the correct null and alternate hypotheses. A. H0: µ1 = µ2 H1: µ1 ≠ µ2 B. H0: µ1 ≤ µ2 H1: µ1 > µ2 C. H0: µ1 = µ2 = µ3 H1: At least one treatment mean is different. b. What is the level of significance? c. Select the test statistic to be used: z, t, chi-square, or F? d. Enter the letter corresponding to the correct decision rule? A. Reject H0 if z > 1.645 B. Reject H0 if F > 4.26 C. Reject H0 if F > 2.01 e. Calculate the value of the test statistic. Round your answer to two decimal places. f. Enter the letter corresponding to the correct decision regarding the null hypothesis. A. Reject H0 B. Do not reject H0 g. Enter the letter corresponding to the correct answer to the question asked in the problem. A. Yes, there is a difference in the productivity of the three employees. B. No, there is not a difference in the productivity of the three employees.
Madhur L.
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