00:01
In this problem, we're going to be looking at the wkb approximation.
00:03
We're going to be applying it to the infinite square well and the finite square well.
00:07
We've got a number of parts.
00:08
We're going to have to motivate this step by step.
00:11
So let's jump into it straight in.
00:14
So to start, obviously, that the total energy is kinetic plus potential.
00:22
That's not in dispute.
00:25
We use the definition of kinetic energy in terms of momentum as p squared over 2m plus you.
00:33
From here, we can solve for momentum.
00:38
With a bit of algebra to be 2m times the difference in energy between total and potential.
00:45
And this is also equal to h over lambda, relating it to its de brogley wavelength.
00:54
So we can just a bit more algebra.
01:09
There's a problem somewhere.
01:10
Let's see.
01:16
No, no, that looks good.
01:19
Right.
01:23
H over 2m.
01:26
E minus u.
01:27
All right.
01:28
Good.
01:29
Perhaps i miswrote it in a problem statement.
01:33
All right.
01:34
So step two, we analyze this expression, and we ask ourselves, as u increases, what happens to lambda? well, as u increases, it eventually gets up to energy e, can exceed e.
01:51
So if u is increasing, this difference is getting smaller.
01:54
It's in the denominator, so lambda has to be getting larger.
02:01
So lambda increases as u decreases.
02:07
As you increases, yes, they increase together.
02:13
So when we're at the extreme case, when we're at this very edge, we expect the potential energy be equal to the total energy.
02:25
In that case, our difference e minus u is zero.
02:28
Thus the denominator is zero, thus lambda goes to infinity, right at these edges...