00:01
Hello students, in this question given as a peloton wheel and their flow rate is given as in this question is 0 .8 m3 per second and the angle of deflection of the jet is 165 degree.
00:16
Now the angle phi will be 180 degree minus 165 is equal to 15 degree and next is given as the coefficient of velocity cv is equal to 0 .985 and the speed ratio is given as speed ratio is equal to 0 .46, jet ratio is 12, head of the water is 180 meter.
01:04
Now the velocity of the jet will be equal to the coefficient of velocity under root 2gh.
01:13
Now we will substitute their values 0 .9, cv is equal to 0 .985 under root 2 into g is 9 .81 meter per second square into 180 meter.
01:30
Now after calculation the jet velocity will be equal to the 58 .54 meter per second.
01:43
Now the speed ratio, we know that the speed ratio is equal to the u1, this is the inlet velocity upon under root 2gh, speed ratio is equal to given as the 0 .46.
02:03
Then after calculation we will get this is equal to 0 .46 under root 2 into 9 .81 into 180.
02:15
So u1 will be equal to the, in this question given as the inlet velocity is equal to the outlet velocity.
02:22
So this will be equal to the 27 .34 meter per second.
02:32
Next in the first part of the question we have to calculate the hydraulic efficiency.
02:42
So formula of hydraulic efficiency is equal to the 2 in bracket v1 jet velocity minus u1 inlet velocity in bracket 1 plus cos phi which is 180 degree minus beta jet angle into u1 upon v1 square.
03:03
Now we will substitute all their values 2 in bracket v1 means 58 .54 minus 27 .34 in bracket 1 plus cos of 15 degree into 27 .34 upon 58 .54 whole square...