00:01
In this question, we have to calculate the efficiency.
00:05
And if the work is done between the pressure 40 bar, p1 is equal to 40 bar or we can say 4 megapascal and p2 is 0 .05 bar and it is 0 .005 mp.
00:26
Now, it is given that we have a rankine cycle under which the work is done.
00:33
So, here we have temperature, this entropy.
00:37
Now, from here, our data will be like this.
00:42
This will be our diagram for the process and it is something like this.
00:51
Now, one second, we have to see here.
00:54
Now, this is our process.
00:56
Now, here we can see that this is process 1, 2, step 3, this is step 4.
01:02
From here, we can see that the pressure of p4 is equal to p1 and p3 is equal to p2.
01:10
Now, from the steam from here, we can calculate h1.
01:14
H1 to be 2800 .8 kilojoule per kg and h3 will be 137 .77 kilojoule per kg.
01:28
Now, from the data, we can from the graph, we can see that s1 is equal to s2 and this value will be sg is equal to sf plus 1 minus x sf, sorry, sfg.
01:42
Now, after substituting the value, this will be 6 .0696.
01:47
Using the data, we can have 0 .47620 plus 1 minus x into 7 .9176.
01:56
Now, after calculating all of this, we get the value of x to be 0 .2935.
02:02
This is 0 .2935...