4) Capsal name Po Afinch vo a pinion gear with tooth number...

4) Capsal name Po Afinch vo a pinion gear with tooth number N-20 transmits 5 HP power at 1000 rpm to a gear with tooth number No-40. Both are straight threaded and the pressure angle is 20 degrees. (1 HP-33000 ft-lb/min) Calculate the gear and pinion diameters (Do and Dr) in inches. b- Calculate the gear surface speed in fmin (1 ft=12 inch) Radial and Tangential forces (F, and F) applied by teeth working with each other lb Calculate in pounds (pounds). d- Since the gears are cut in \"Commercial\" quality, calculate the dynamic gear load using only the surface speed. Are the speeds appropriate for this type of trimmed gear? Since Lewis Form Factor is Y=0.5, at least how many inches must be the thickness of the gear pair made of steel material with yield stress Sy=74 000 lb/inch$^2$ and fatigue stress Sg half of this? - If the thickness of the gear pair is made as I inch, what will be the factor of safety?

Transcript

00:01 High so we are given that a 21 tooth pinion rotating at a speed of n is equal to 18 hundredths of revolutions per minute measures with 33 tooth of gear in a simple pure gear set.

00:28 Reliability is given 0 .9 that is standard for 25 degree full depth teeth.

00:35 The diamaterial pitch is given as 6 and phase width is 2 .000 of inches.

00:46 So you have to follow all these steps to determine the bending stress using agma equations.

00:55 So in a part in the greatest which do we expect to fail first pinion or the gear that we have to answer.

01:05 As we can see the pinion has less number of teeth as compared to gears that is why the pinion will fail first.

01:20 So this is the answer for first.

01:22 Now let's have a look to b part in which we have to calculate the pitch diameter and pinion using the pitch line velocity greatest.

01:34 So since we remember that the diameter can be calculated as d is equal to np by pd.

01:42 Substitute all the values as i have dictated above you will get the diameter as 3 .5 inches.

01:50 In similar way we have to find the velocity also which can be given by dn by 2.

01:59 So on substituting the values you will get it's to be as 1649 feet per minute.

02:11 So these are the required answers to b part of this question.

02:17 Now in c part we need to calculate dynamic factor kv.

02:24 Dynamic factor by using the equation 11 .16 can be given by b is equal to 0 .25 times of 12 minus of qv whole to the power 0 .6667.

02:38 So just plugging the values.

02:42 So first of all b should be equal to 0 .520.

02:49 Now let us calculate the a parameter which is equal to 50 plus 56 1 minus of b will comes out equal to 76 .878.

03:01 So by using this specific heat capacity at constant volume cv can be calculated as a by a plus under root over v minimum divided by feet means in feet that whole to the power b.

03:19 So cv will comes out after substituting the value 0 .80.

03:24 So this is what the dynamic factor and answer to c part.

03:29 Now let's move to d part in which we have to calculate the geometric factor...

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