Question

A ball is thrown vertically upward. After $t$ seconds, its height $h$ (in feet) is given by the function $h(t) = 56t - 16t^2$. After how long will it reach its maximum height?\nDo not round your answer.

Name: A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t) = 56t - 16t^2. After how long will it reach its maximum height?not round your answer.
Uploaded: 2022-03-22T16:03:57-08:00
Duration: 2 min 24 s
Channel: Hafiz Mohsin Zahid
Description: A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t) = 56t - 16t^2. After how long will it reach its maximum height?not round your answer.

          A ball is thrown vertically upward. After $t$ seconds, its height $h$ (in feet) is given by the function $h(t) = 56t - 16t^2$. After how long will it reach its maximum height?\nDo not round your answer.

A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t) = 56t - 16t^2. After how long will it reach its maximum height?not round your answer.

Added by Jonathan B.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Hafiz Mohsin Zahid

03/22/2022

Step 1

Step 1: To find the minimum height of the ball, we need to find the vertex of the quadratic function h = 55 - 16f. Show more…

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Texts: A ball is thrown vertically upward. After f seconds, its height h in feet is given by the function h = 55 - 16f. After how long will it reach its minimum height? Do not round. Answer: 6 seconds.