00:01
So here they're giving us an equation and they simply want the properties of the wave.
00:04
We have an equation y of xt, so a multivariate equation.
00:11
This will equal 6 .50 millimeters times sine of 2 pi of t divided by 0 .360 seconds.
00:27
And then minus x over point z 280 meters.
00:43
We're going to relate this to the general equation of y of x and t, equaling a sine of 2 pi times time over period minus x over the wavelength lambda.
01:00
So for part a, when it's asking for the amplitude, this is simply going to be 6 .50 millimeters or we can convert and say 0 .0650 meters.
01:15
For part b, they want the wavelength.
01:18
This is simply going to be what the denominator of the x term, so 0 .280 meters.
01:27
So that would be the wavelength.
01:28
And then for part c, they're asking for the period and the frequency.
01:32
So the period is 0 .036 seconds.
01:38
And so f, the frequency will simply be equal to 1 over the period, or 1 divided by 0 .036...