00:01
Hello students, in this question we have two gaseous streams containing the same fluid entering a mixing chamber.
00:09
So this is the mixing chamber with two fluids entering.
00:15
So we are given that for the first gas, the entrance cross sectional area a1 is equal to 500 cm2, entrance velocity v1 is equal to 130 mps, and the entrance density rho1 is equal to 1 .6 kgm per m3.
00:40
Similarly for second gas, we are given that a2, entrance cross sectional area is 400 cm2, and the mass flow rate m2 is given as 8 .84 kgm per second.
01:00
And then we have specific volume v2, which is entrance velocity v1, and this is specific volume v2 is given as 0 .502 m3 per kg.
01:24
Now the exit velocity, we have exit velocity v is equal to 130 mps, and specific volume v is equal to 0 .437 m3 per kg.
01:43
Now let's solve everything.
01:45
So the total mass leaving the chamber, so we can use the equation m1 is equal to rho1 a1 times v1.
02:00
So this is the total mass flow rate of the gas can be calculated using this equation.
02:06
So rho1 is equal to 1 .6 times a1 is equal to 500 cm2 times v1, velocity 1 is equal to 130.
02:23
So you will get the value will be equal to, so you have to convert that into m2.
02:32
So you can divide this by 10 ,000, right? 10 ,000 and you will get, you will get the value will be equal to, so that is equal to 10 .4 kg per second.
02:51
So that is the mass flow rate.
02:54
Now second part is the velocity of the gas b...