A survey found that women's heights are normally distributed with mean 63.5 in. and standard deviation 3.9 in. The survey also found that men's heights are normally distributed with mean 68.1 in and standard deviation 3.4 in. Consider an executive jet that seats six with a doorway height of 55.7 in. Complete parts (a) through (c) below. a. What percentage of adult men can fit through the door without bending? The percentage of men who can fit without bending is % (Round to two decimal places as needed.)
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7 inches for men. To find the z-score, we use the formula: z = (x - μ) / σ where x is the value we want to find the z-score for, μ is the mean, and σ is the standard deviation. In this case, x = 65.7 inches, μ = 68.1 inches, and σ = 3.4 inches. Plugging in the Show more…
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