00:01
So by equating the sum of moments about point a to zero, will eliminate reaction forces at a.
00:08
So we can write the expression for normal reaction force at e.
00:13
So m of a equals zero.
00:17
So n of e is equal to, sorry, n -e times a .e minus 2130w cosine cosine of theta plus 500w sine.
00:33
Of theta is equivalent to zero.
00:36
So then ne is equivalent to 2130w cosine of theta minus 500 w sine of theta over ae.
00:53
So then plugging in what we know, n e is equivalent to 2130 times 981 cosine theta.
01:07
Minus 500 times 981 sine of theta over a .e.
01:17
So that's essentially 2089530 cosine of theta minus 490500 sine of theta over ae.
01:35
So now we'll need to determine the length of ae.
01:39
So a .e is equivalent to the square root.
01:43
Of 1945 squared plus 1060 squared minus 2 times 1945 times 1060 cosine of beta.
02:00
So then we know that ae is equivalent to the square root of 4906625 minus 412340 cosine cosine of beta.
02:12
So now we can determine angle a.
02:19
So sine of a over 1060 is equivalent to sine of theta over 1945...