Below you are given the initial contents of memory and the...

Below you are given the initial contents of memory and the registers in the Mano machine. Assume that three instruction cycle (fetch, decode, possible indirect, and execute) is carried out. a) Write the names of the instructions which are executed.: b) After the instruction cycles are carried out, the PC, AC, E equals : Initial Register Contents E = 1 AC = 8013 PC = 01F DR=1234 The contents of memory at other all addresses and registers are 00FF. Memory: Address Contents 01E 1020 01F A800 020 7010 021 1020 022 4803 023 8801 800 9022 801 1234 802 0020 803 001E

Transcript

00:01 Hello students, let's go over the instruction cycle step by step for the given indirect instruction with the operation code of and and the address part of the 0ab.

00:11 So, we will first go with the fetch phase.

00:15 In a fetch phase, you will perform as the program counter counts contains the address of the next instruction which is 053.

00:30 So, the instruction address at 053 is fetched and stored in the instruction of ir.

00:39 Now, once the address is fetched, you need to decode the phase.

00:43 In decode phase, the instruction in the instruction register is decoded to determine the operational code and and address and address part as the as the and and the address part as the 0 of ab, 0 of ab.

01:07 Now, in an execute phase, in an execute phase where the address part as the 0ab is used to access the memory word at the address 0ab.

01:24 So, the memory word at 0ab contains it contains the cf25.

01:31 So, the content of this memory is loaded into the data register that is into the dr.

01:37 So, it is loaded into the dr register.

01:39 Then the indirect access as the indirect access.

01:46 So, the content of the direct register that is the cf of 25 is used an address to access the memory word at the address of cf25.

01:59 The memory word at the address of cf25, it contains the a620.

02:06 So, the content of this memory is loaded into the ac that is the accumulator.

02:12 It is loaded into an accumulator...

Question

Please give Ace some feedback