Question

Consider an over-damped oscillator with mass 0.8 kg and spring constant 0.275 N/m. The damping constant is 3.7 N/m * s. Part A - What is the value of \gamma for this system? 3.94 \frac{1}{s} Incorrect; Try Again; 4 attempts remaining Part B - If we start the system from the equilibrium position but with velocity 5 cm/s what will be its position after 0.15 s? 0.567 cm

          Consider an over-damped oscillator with mass 0.8 kg and spring constant 0.275 N/m. The damping constant is 3.7 N/m * s.
Part A - What is the value of \gamma for this system?
3.94
\frac{1}{s}
Incorrect; Try Again; 4 attempts remaining
Part B - If we start the system from the equilibrium position but with velocity 5 cm/s what will be its position after 0.15 s?
0.567 cm

Consider an over-damped oscillator with mass 0.8 kg and spring constant 0.275 N/m. The damping constant is 3.7 N/m * s.
Part A - What is the value of γfor this system?
3.94
(1)/(s)
Incorrect; Try Again; 4 attempts remaining
Part B - If we start the system from the equilibrium position but with velocity 5 cm/s what will be its position after 0.15 s?
0.567 cm

Added by Ramon T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

11/25/2022

Step 1

Given: Mass (m) = 0.8 kg Spring constant (k) = 0.275 N/m The angular frequency (ω) can be calculated using the formula: ω = √(k/m) Substituting the given values: ω = √(0.275 N/m / 0.8 kg) Show more…

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Texts: BOTH PART A AND B SHOULD INCLUDE UNITS. Both of the answers above are incorrect. I am 90% sure that 1/s is the correct unit for part A. Consider an over-damped oscillator with mass 0.8 kg and spring constant 0.275 N/m. The damping constant is 3.7 N/m * s. Part A - What is the value of ω for this system? Part B - If we start the system from the equilibrium position but with velocity 5 cm/s, what will be its position after 0.15 s?