Question

Monochromatic light of wavelength 463 nm is incident on a narrow slit. On a screen 1.62 m away, the distance between the second diffraction minimum and the central maximum is 1.21 cm. (a) Calculate the angle of diffraction $\theta$ of the second minimum. (b) Find the width of the slit.

Name: Monochromatic light of wavelength 463 nm is incident on a narrow slit. On a screen 1.62 m away, the distance between the second diffraction minimum and the central maximum is 1.21 cm. (a) Calculate the angle of diffraction θ of the second minimum. (b) Find the width of the slit.
Uploaded: 2019-07-24T12:26:56-08:00
Duration: 2 min 27 s
Channel: Ben Nicholson
Description: Monochromatic light of wavelength 463 nm is incident on a narrow slit. On a screen 1.62 m away, the distance between the second diffraction minimum and the central maximum is 1.21 cm. (a) Calculate the angle of diffraction θ of the second minimum. (b) Find the width of the slit.

          Monochromatic light of wavelength 463 nm is incident on a narrow slit. On a screen 1.62 m away, the distance between the second diffraction minimum and the central maximum is 1.21 cm. (a) Calculate the angle of diffraction \(\theta\) of the second minimum. (b) Find the width of the slit.

$Monochromatic light of wavelength 463 nm is incident on a narrow slit. On a screen 1.62 m away, the distance between the second diffraction minimum and the central maximum is 1.21 cm. (a) Calculate the angle of diffraction θ of the second minimum. (b) Find the width of the slit.$

Added by Joseph M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ben Nicholson

07/24/2019

Step 1

The distance between the second diffraction minimum and the central maximum can be used to find the angle of diffraction θ. We can use the small angle approximation, which states that for small angles, the tangent of the angle is approximately equal to the angle Show more…

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Texts: Can you answer and explain. Please and thank you. Monochromatic light of wavelength 463 nm is incident on a narrow slit. On a screen 1.62 m away, the distance between the second diffraction minimum and the central maximum is 1.21 cm. a) Calculate the angle of diffraction θ of the second minimum. (b) Find the width of the slit. (a) Number: 0.427942 Units: degrees (b) Number: 121000 Units: nm