Find a basis for the subspace \begin{equation*} W = \left\{ \begin{bmatrix} 2a + 5b & 6b \\ 4a & 9b \end{bmatrix} \in \mathbb{R}^{2 \times 2} \mid a, b \in \mathbb{R} \right\} \text{ of } \mathbb{R}^{2 \times 2}. \end{equation*} A basis for $W$ is $\left\{ \begin{bmatrix} 1 & 0 \\ 4 & 0 \end{bmatrix}, \begin{bmatrix} \boxed{ } & 6 \\ \boxed{ } & \boxed{ } \end{bmatrix} \right\}$.
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Step 1: To find a basis for the subspace W, we need to find a set of vectors that span W and are linearly independent. Show more…
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