00:01
Let's discuss this question.
00:03
So here it is given that for the trans, that is mncl4 f2 3 minus ions.
00:09
It is in the 3eg ground state.
00:13
So here we need to find the possible electronic states and also which transition or spin allowed by the ground state.
00:20
So first of all, let's see the spin selection rule.
00:32
So here we can say delta s is equal to 0.
00:36
So this will be equal to.
00:40
So then we can say spin is allowed.
00:46
If delta s is not equal to zero.
00:49
So here we can say spin is forbidden.
00:58
And here we can say delta s is given by s2 minus s1.
01:06
So if this is equal to zero, so here we can say s1 and s2 are the spin quantum.
01:19
Numbers.
01:23
Also here we need to keep in mind that no change occurs in spin multiplicity or spin during electronic transition.
01:53
So here for example trans mncl4 f2 3 minus will be equal to mn3 plus so this will be equal to b4 minus mn 3 plus that is equal to d4.
02:26
So here we can say further that mn3 plus that is equal to b4 is equal to the electronic state or electronic configuration.
02:51
So here we can say mn 3 plus that is equal to b plus will have.
03:20
Here let's represent t2g and eg so here we can say this will be eg and this will be t2g.
03:34
So here let's draw here we can say this is eg and here we will be having t2g.
03:53
So here we can say this is the ground state...