Question

The proportion of the first 36 customers who wait for more than 15 minutes at Certain Restaurant between 5 p.m. and 9 p.m. is recorded for 90 independent replications of a simulation model with identical initial conditions. The recorded proportions have sample mean 0.28. Construct a 95% confidence interval for this proportion. ($z_{0.1} = 1.28, z_{0.05} = 1.64, z_{0.025} = 1.96$) half-width of the interval: central value: lower bound: upper bound:

          The proportion of the first 36 customers who wait for more than 15 minutes at Certain
Restaurant between 5 p.m. and 9 p.m. is recorded for 90 independent replications of a
simulation model with identical initial conditions. The recorded proportions have sample
mean 0.28. Construct a 95% confidence interval for this proportion.
($z_{0.1} = 1.28, z_{0.05} = 1.64, z_{0.025} = 1.96$)
half-width of the interval:
central value:
lower bound:
upper bound:

The proportion of the first 36 customers who wait for more than 15 minutes at Certain
Restaurant between 5 p.m. and 9 p.m. is recorded for 90 independent replications of a
simulation model with identical initial conditions. The recorded proportions have sample
mean 0.28. Construct a 95% confidence interval for this proportion.
(z0.1 = 1.28, z0.05 = 1.64, z0.025 = 1.96)
half-width of the interval:
central value:
lower bound:
upper bound:

Added by Emily H.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert James Kiss

08/26/2023

Step 1

- The sample mean of the recorded proportions is 0.28. - The simulation model was replicated 90 times. - The confidence level is 95%. - The critical z-values for a 95% confidence level are z0.025 = 1.96 and z0.05 = 1.64. Show more…

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Texts: HELP 🥹‼️ The proportion of the first 36 customers who wait for more than 15 minutes at a Certain Restaurant between 5 p.m. and 9 p.m. is recorded for 90 independent replications of a simulation model with identical initial conditions. The recorded proportions have a sample mean of 0.28. Construct a 95% confidence interval for this proportion. z0.1 = 1.28, Z0.05 = 1.64, z0.025 = 1.96. Half-width of the interval: Central value: Lower bound: Upper bound: