00:01
All right, so we're told when 4 .348 grams of sodium nitroxide sample was dissolved in 100 grams of water in the calorimeter, there was a temperature rise of 23 .6 to 47 .4 degrees celsius.
00:17
The question is to calculate the delta h in kilojoule per mole of dissolution.
00:25
So here's the thing.
00:26
The heat that was released from the dissolution of the sodium would be the mass of water times the specific heat capacity of water multiplied by the change in the temperature plus the heat capacity of the calorimeter times the change in temperature.
00:48
And so here you have 100 multiplied by 4 .18 joule per gram per degree celsius times the change in temperature is 23 .8 plus the heat capacity of calorimeter is 35 .5 times 23 .8.
01:04
And this would give you 10 ,793 .3 joules, which is in kilojoules, right, that's 10 .793 kilojoules, right, exactly.
01:23
But to find the delta h, so this is saying that 4 .348 grams of this produce this amount of heat.
01:35
So what would per mole, so one mole of sodium nitroxide has a mass of 40 grams...