00:01
Firstly, let's summarize the given data.
00:04
Mass of sulfur dioxide is 4 .77 grams.
00:15
And mass of sulfur trioxide is 5 .26 grams.
00:29
The task in this problem is to find the theoretical yield of the sulfur trioxide.
00:37
In grams and percent yield.
00:46
Firstly, let's write reaction equation.
00:51
Sulfor dioxide plus oxygen gas equals sulfur trioxide.
01:02
Let's balance.
01:03
Here will be two and here will be two.
01:08
Let's find the number of moles of sulfur dioxide.
01:12
We know that molar mass of sulfur dioxide.
01:18
Is 64 .06 grams per mole and the number of moles of sulfur dioxide will be 4 .77 grams divided by molar mass 64 .06 grams per mole and we obtain 0 .077 .4 .6 grams per mole and we obtain 0 .07446 moles.
01:57
Next we see reaction equation and can conclude that from two molecules of sulfur dioxide we obtain two molecules of sulfur trioxide...