00:01
Hello students, let's see the equation.
00:02
So it's given that vl is equal to 400 v.
00:06
Then potential difference across three phases that is vry is equal to 400 0 degree.
00:13
Vyb is equal to 400 minus 120 degree volt.
00:19
Then vv is equal to 400 minus 120 degree volt.
00:24
And impedance is given, phase currents are given.
00:27
So the line current would be ir is equal to iry minus ibr.
00:35
So that is equal to 40 36 .85 degree minus 40 120 degree.
00:42
So this would be equal to 53 minus j 10 .64.
00:46
So that is equal to 53 .07 minus 11 .56 degree ampere.
00:52
And now iy is equal to iry minus iyb minus iry.
01:03
So that is equal to 40 minus 173 .13 degree minus 40 angle 36 .86 degree.
01:11
So when we solve this, we get the value to be equal to 77 .28 angle minus 158 .13 degree ampere.
01:18
And similarly for the ib which is equal to ibr minus iyb...