8. NMR: Worksheet 1 - ¹HNMR Match each of the ¹H NMR spectra...

8. NMR: Worksheet 1 - ¹HNMR Match each of the ¹H NMR spectra with one of the following compounds: $CH_3$ $CH_2$C(=O)$CH_2$ $CH_3$ $CH_3CH_2CNO_2$ $CH_3CH_2CH_2NO_2$ $CH_3CH_2NO_2$ $CH_3CH_2CHBr_2$ $CH_3CH_2CH_2CH_3$ $CH_3CH_2CH_2CH_3$ $CH_3CH_2CH_2CH_3$ $\delta$ (ppm) frequency $\delta$ (ppm) frequency $\delta$ (ppm) frequency

Transcript

00:05 We are given some compounds, organic compounds, and asked to match them with the corresponding proton nmr spectrum in this question.

00:15 So if we look at the first spectrum, we see that there are two signals and this is a proton nmr spectrum.

00:22 So it means that there are two types of protons in this compound.

00:27 And the ratio between those two, those two type of protons is 1 to 6.

00:33 So if we look at the molecules that we are provided with, there's only one molecule that meets these conditions.

00:42 So it's the last molecule, which is this.

00:52 It's a propyl bromide, a branched version of it.

01:04 So this, if you take a closer look at uc, has two types of protons, the methyl protons and the metil protons.

01:16 Proton and it has a 1 to 6 ratio there's one of the methane proton and there's 6 methal protons and then the methane signal should be really downfield because of its proximity to the bromine which is the case in this nmo spectrum so the first spectrum corresponds to this molecule and then if we take a look at the second spectrum you see that the spectrum has three signals corresponding to three types of protons and then they have an integration ratio of 2 to 2 to 3 and the only compound that meets those criteria is this so it has two twos and 1 3 when we look at the different types of protons it has and then we see that the signals have split into two triplets and one multiple so here this methyl protons will split into a triplet because of the neighbor neighboring methalin protons and then this methane protons will give rise to a signal that split into two plus one another triplet again and the central metylene protons will give rise to a multiple because of the two different types of protons that it has around it.

03:23 So the structure corresponds to this molecule.

03:28 The nmr spectrum corresponds to this molecule.

03:32 This is for the spectrum b.

03:36 And then if we look at the third nmr spectrum, it has three signals again and the integral ratio of 3...

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