00:01
Hello students, referring to the given question, the side is given as 90 cm or 90 x 10 -2 m and the charge is uniformly spread and the magnitude of the charge is 8 .50 nc.
00:21
We have to find the electric field at the point 100 mm above the center of the sheet.
00:42
Therefore, the formula is e is equal to sigma by 2 into epsilon 0 where sigma is the surface charge density which can be calculated as sigma is equal to charge divided by the area.
01:09
Therefore, on calculating this charge is 8 .50 x 10 -9 c divided by area is 0 .9 x 0 .90 otherwise 90 x 10 -2 m the whole square.
01:30
Therefore, we will be obtained with 8 .50 x 10 -9 c divided by 0 .81 m2.
01:42
Therefore, sigma is equal to that is the surface charge density 1 .049 x 10 -8 c m2.
01:55
Now with this we have to calculate the electric field.
01:58
So, on plugging this value the formula of electric field e is equal to 1 .049 x 10 -8 c m2 divided by 2 into epsilon 0 is the permittivity of vacuum that is 8 .85 x 10 -12 c m2 divided by n m2...