00:01
All right, so let's say we have two forces.
00:02
Force one is directed at an angle of 57 degrees above the negative x axis and has a magnitude of 8 newtons.
00:13
So let's say this is f1.
00:15
Force 2 is directed at an angle 54 .1 below the negative x axis like this and has a magnitude of 5 .4 newtons.
00:30
And we want to know what is the resultant force when we're adding these two.
00:37
So the x component of our resultant force is going to be, you know, negative 8 newtons times the cosine of 57 plus, it's really going to be a minus, minus 5 .4 newtons times the cosine of 54 .1.
00:57
Because those are our x components of our two vectors.
01:02
So if you do 54 .1, the cosine of that times, sorry, times 5 .4, the negative sign, plus the cosine of 57 times 8 with the negative sign.
01:17
We should get a resulting component of negative 7 .52 newtons.
01:24
And then for the y component, we'll do kind of a similar thing.
01:27
We'll have 8 newtons times the sign of 57 minus 5 .4 newtons times the sign of 50, sorry, 54 .1.
01:43
So we do that 54 .1, we do the sign of that times 5 .4 at the negative sign, and we're adding to this...