00:01
All right, hello, in this question we'll give you the setup.
00:02
We have charge q1, which is on the left side at the origin, and it has a magnitude of 25q for its charge.
00:09
And then 1 .5 meters away, i have a charge q2, which is the same sign, they're both positive, and that only has a charge of 1q.
00:17
And then i place a third bead with some unknown charge, i'm going to call it big q, a distance x away from the leftmost charge.
00:24
And we want to figure out what this distance x here is, such that our red charge is in equilibrium.
00:31
So in order to do that, we're going to need to go ahead and draw the forces on this.
00:34
So i'm going to assume that q is a positive charge, so i'm going to have a force from q1 pushing it away, pushing it to the right, and an equal and opposite in direction is going to be the force from q2 pushing it to the left.
00:50
So my sum of the forces on this guy are going to be force of q1 minus force of q2, that's going to equal zero because i'm in equilibrium...