00:03
In this question, we will be dealing about the radioactive decay of iridium 192.
00:08
The information given in the question are shown below.
00:12
Initial mass of iridium taken is 4 grams.
00:16
And the question asked is, the mass of iridium that remains after 55 days.
00:31
In second question, we got to estimate the half -life time of iridium 192 by interpreting the graph given in the 2.
00:39
The question.
00:43
The third question, we are asked to find the number of days it would take for one third of the original mass of iridium 192 decay.
00:55
First let us find the mass of iridium that remains after 55 days.
01:01
To find the mass that remains after 55 days, we use the following formula where n final, that is mass of final iridium present is equal to n.
01:14
Multiplied with half rise to the power t by t half t half is the half lifetime of iridium 192 and t is the time in this case it is 55 days we know n0 initial mass of iridium taken as 4 gram multiplied with half and t is 55 days and by interpreting the graph we find the value of t half as 75 days by carrying out the calculation we find the final mass of iridium reminding after 55 days of decay as 2 .4 grams.
01:53
Hence, the mass that remains after 55 days of decay is 2 .4 grams...